Question

How many grams of `CH_4` are present in `5.14*10^23` molecules of `CH_4`?

Answer 1

Well, `6.022xx10^23` methane molecules have a mass of `16.01*g`.

Explanation:

So,

`(5.14xx10^23*"methane molecules")/(6.022xx10^23*"methane molecules mol"^-1)xx16.01*g*mol^-1`

`~=` `13*g`