Question

How do you evaluate `log_3 1`?

Answer 1

I found that it is equal to zero:

Explanation:

You may use the definition of log:
`log_ba=x`
so that: `a=b^x`

we now need to find our `x` in:
`log_3(1)=x`

using our definition we see that the only possible value for `x` is zero because:
`1=3^0`

Answer 2

`log_3 1 = 0`

Explanation:

Written in log form, the question being asked is,"

"1 is which power of 3? " `3^0 =1`

Or

"Using a base of 3, what index will give 1 as the answer?"
`3^0 =1`

Log form and index form are interchangeable.

`log_3 1 = x " " rArr 3^x = 1`

`x = 0`