How many grams of #CuF_2# are needed to make a 600 mL solution with a molarity of 0.250 M?

1 Answer
anor277
Aug 18, 2016

Approx. #15*g#

Explanation:

#"Concentration"# #=# #"number of moles"/"volume of solution"#

Thus #0.250*mol*L^-1# #=# #n_"copper fluoride"/(0.600*L)#

And #n_"copper fluoride"=0.250*mol*cancel(L^-1)xx0.600*cancelL#

#=# #0.150*mol" copper fluoride"#

#"Mass of cupric fluoride"# #=# #0.150*molxx101.54*g*mol^-1# #=# #??g#

Related questions
See all questions in Molarity
Impact of this question
1676 views around the world
You can reuse this answer
Creative Commons License