How do you find #h(10)# given #h(x)=-x^2-x#?

1 Answer
Aug 18, 2016

#h(10) = 110#

Explanation:

#h(color(red)(x))=-color(red)(x)^2-color(red)(x)#

#h(10)# means that x = 10. So each x is replaced by 10

#h(color(red)(10))=-color(red)(10)^2-color(red)(10)#

#h(color(red)(10)) = -100 -10 = -110#

Remember that #y = f(x)#

#y = h(x)#

#y = h(10) = -110#

means that for this function, when

#x = 10, y= -110#