Question

How do you solve `25^(x-1)=125^(4x)`?

Answer 1

`x=-1/5`

Explanation:

Since `25=5^2` and `125=5^3` you can rewrite:

`5^(2(x-1))=5^(3(4x))`

that implies:

`2(x-1)=3(4x)`

that's

`2x-2=12x`

`10x=-2`

`x=-1/5`