115 mL of a 2.35 M potassium fluoride solution is diluted with 1.28L of water. What is the new concentration in molarity?

1 Answer
anor277
Aug 19, 2016

#[KF]# #=# #0.194*mol*L^-1#

Explanation:

#"Concentration"# #=# #"Moles of solute"/"Volume of solution"#

#(0.115*Lxx2.35*mol*L^-1)/(0.115*L+1.28*L)#

#=# #(0.270*mol)/(1.395*L)# #=# #0.194*mol*L^-1#.

Please note that the wording of the problem said that the initial #0.115*L# volume was diluted with #1.28*L# FRESH SOLVENT. Had it said #"diluted to 1.28"*L#, the volume would change accordingly. Do you see why I make the distinction?

Such a solution would be slightly basic. Why?

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