If #g(a)=3^(3a-2)#, what is #g(1)#?

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Answer 1 · 2016-08-21T12:51:48

#g(1)=3#.

To find #g(1)# from #g(a)=3^(3a-2)#, we have to just replace #a# by

#1# in the formula for #g(a)# as shown below :

#g(1)=3^(3*1-2)=3^(3-2)=3^1=3#.

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Answer 2 · 2016-08-21T12:54:05

3

g(1) = #3^(3.1-2)#
= #3^1#