Question

Question #3a0ab

Answer 1

`0.01m`

Explanation:

We know for sonic and ultra sonic waves the velocity `v` is related to frequency `n` and wavelength `lambda` by the following expression

`v=nlambda`

Inserting given values we get
`1500=0.15xx10^6lambda`
`lambda=1500/(0.15xx10^6)`
`lambda=0.01m`