How do you graph the line that goes through (3, 0) and has a slope of -3/4?

1 Answer
Aug 31, 2016

y=-3/4x+c

Explanation:

In the general equation of a line y=mx+c
m is the gradient and c is the value of the y intercept

So the equation of the line is y= -3/4x +c
This passes through (3,0)
So 0=-3/4*3+c

So c=9/4
The equation of the line is

y=-3/4x+9/4

Or 4y=9-3x
graph{4y=9-3x [-10, 10, -5, 5]}