Question

How do you find the arc length of the curve `y=e^(x^2)` over the interval [0,1]?

Answer 1

`≈2.12762` numerical solution

Explanation:

`S = int_0^1 sqrt(1+(y')^2) dx`

`= int_0^1 sqrt(1+(2x e^(x^2))^2) dx`

`≈2.12762` numerical solution