How do you solve #9/8=(k+6)/6#?

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Answer 1 · 2016-09-01T19:58:45

#k=3/4#

#9/8=(k+6)/6#

#9*6=8*(k+6)#

#54=8k+48#

#54-48=8k#

#6=8k#

#k=6/8#

#k=3/4#

Answer 2 · 2016-09-01T20:00:33

#k = 3/4#

If an equation has one fraction on each side of the equal side, we can get rid of the brackets by cross-multiplying.

#9/8 = (k+6)/6#

#8(k+6) = 9xx6#

#8k +48 = 54#

#8k = 6#

#k = 6/8 = 3/4#