Question

How many moles of `MgS_2O_3` are in 235 g of the compound?

Answer 1

A little bit under `2` `"moles"`

Explanation:

`"Molar quantity"` `=` `"Mass"/"Molar mass"`

`=` `(235*cancelg)/(136.4*cancelg*mol^-1)` `=` `??mol`