How do you solve #3(6)^(2x-3)=648#? Precalculus Properties of Logarithmic Functions Natural Logs 1 Answer CW Sep 5, 2016 #x=3# Explanation: #3(6)^(2x-3)=648# #(6)^(2x-3)=648/3=216# #(6)^(2x-3)=216=6xx6xx6=6^3# #2x-3=3 # #=>x=3# Answer link Related questions What is the natural log of e? What is the natural log of 2? How do I do natural logs on a TI-83? How do I find the natural log of a fraction? What is the natural log of 1? What is the natural log of infinity? Can I find the natural log of a negative number? How do I find a natural log without a calculator? How do I find the natural log of a given number by using a calculator? How do I do natural logs on a TI-84? See all questions in Natural Logs Impact of this question 2379 views around the world You can reuse this answer Creative Commons License