Which equivalence factor should you use to convert from 4.25 moles of aluminum (Al) to atoms of aluminum?

1 Answer
anor277
Sep 5, 2016

We use #"Avogadro's number"# to give the number of aluminum atoms.

Explanation:

One mole of stuff specifies #N_A, "Avogadro's number, "# #6.02214xx10^23*mol^-1# individual particles.

We have #4.25*mol#, i.e. #4.25*cancel(mol)xx6.02214xx10^23*cancel(mol^-1)# #"aluminum atoms"#, approx. #25xx10^23# #"aluminum atoms"#. What is the mass of this number of atoms?

Related questions
See all questions in Unit Conversions
Impact of this question
2342 views around the world
You can reuse this answer
Creative Commons License