How do you expand #log(5*3)#?

2 Answers
Sep 7, 2016

I used a property of logs:

Explanation:

You can change the product of arguments into a sum of logs as:

#log(5*3)=log(5)+log(3)#

When you have these property of logs and you have a doubt try using your calculator and natural logs to check them:

try first: #ln(5*3)=ln(15)#

and then: #ln(5)+ln(3)#

they should give the same result!

Sep 7, 2016

#log5+log3#

Explanation:

Using the following #color(blue)"law of logarithms"#

#color(orange)"Reminder " color(red)(bar(ul(|color(white)(a/a)color(black)(logx+logy=log(xy))color(white)(a/a)|)))#

#rArrlog(5xx3)=log5+log3#