How do you solve the quadratic #9a^2+3=-27# using any method?

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Answer 1 · 2016-09-07T18:04:26

There is no solution

first subtract by #3#

#9a^2=-30#

divide by #9#
#a^2=-30/9#

now take the square root but wait we can't do that for a negative so there is no solution.

You can try the quadratic formula but lets see what happens when we try that approach

#(-b +-sqrt(b^2 - 4ac))/(2a)#

#(0 +-sqrt(0 - 4*30))/(2) = sqrt(-120)/(2)#

Okay wait we see the same thing here, we cant really take the square root of a negative.

Lastly anytime you have an even exponent the answer will always be positive so this is rational enough to consider this an equation with no solution.