How do you write #(x+2)/3-(x-3)/4# as a single fraction?

1 Answer
Sep 8, 2016

#(x+17)/12#

Explanation:

Treat algebraic fractions in the same way as arithmetic fractions.

We need a common denominator - in this case it is 12.
Find the equivalent fractions:

#((x+2))/3 xx 4/4" - "( (x-3))/4 xx3/3#

=#(4(x+2))/12 - (3(x-3))/12#

=#(4x+8-3x+9)/12 " "larr# simplify the numerator

=#(x+17)/12#