Question

How do you solve `sqrt(2x-6)<4`?

Answer 1

`x = 11`

Explanation:

To begin,
`sqrt(2x-6) < 4`

We can't do anything with that square root there, so let's get rid of it! We square both sides.
`sqrt(2x-6)^2 < 4^2`
`2x-6 < 16`

Now, we need to get rid of constants before coefficients, so we add 6 to both sides.
`2x -6+6 < 16+6`
`2x < 22`

Now, we can get rid of the 2!
We divide both sides by 2.
`(2x)/2 < 22/2`
`x = 11 square`