How do you simplify the expression #secthetacottheta#?
1 Answer
Sep 10, 2016
Explanation:
Using the
#color(blue)"trigonometric identities"#
#color(orange)"Reminder " color(red)(bar(ul(|color(white)(a/a)color(black)(sectheta=1/(costheta)" and " cottheta=(costheta)/(sintheta))color(white)(a/a)|)))#
#rArrsecthetacottheta=1/(cancel(costheta))xxcancel(costheta)/sintheta=1/(sintheta)#
#color(orange)"Reminder " color(red)(bar(ul(|color(white)(a/a)color(black)(csctheta=1/(sintheta))color(white)(a/a)|)))#
#rArr1/(sintheta)=csctheta# Thus:
#secthetacottheta=csctheta#