How do you solve #2/3x+1=1/2x#?

1 Answer
EZ as pi
Sep 11, 2016

#x = -6#

Explanation:

When you have an EQUATION with fractions, you can get rid of the denominators by multiplying by the LCD. (In this case LCD =6)

#(cancel6^2xx2)/cancel3x+6xx1=(cancel6^3xx1)/cancel2x#

#4x+6 = 3x" "larr# no fractions!

#4x-3x = -6#

#x = -6#

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