How do you solve #1/12|2x-7|+11<=12#?

1 Answer
Binayaka C.
Sep 11, 2016

Solution: # -5/2 <= x <= 19/2# In interval notation; #[-5/2,19/2]#

Explanation:

1) #1/12|2x-7| +11 <=12 or 1/12|2x-7| <=1 or |2x-7|<=12 or 2x-7<=12 or 2x<=19 or x<=19/2# OR
2)#1/12|2x-7| +11 <=12 or 1/12|2x-7| <=1 or |2x-7|<=12 or 2x-7>= -12 or 2x>= -5 or x>= -5/2#
Solution: # -5/2 <= x <= 19/2# In interval notation; #[-5/2,19/2]#[Ans]

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