What is the domain of #f(x)=sqrt(4-x^2)#?

1 Answer
Sep 11, 2016

#-2 <= x <= 2#

Explanation:

We are dealing with a square root here. Since squares are non-negative, we can only obtain a valid value from the square root if it involves non-negative values

#4 - x^2 >= 0#

#=> 4 >= x^2#

#=> x^2 <= 4#

#=> -2 <= x <= 2#