How do you simplify the expression #(sinx-cosx)/(sinxcosx)#?
2 Answers
Sep 11, 2016
Explanation:
Use trig identity:
sin 2x = 2sin x.cos x
The expression becomes
Since
This simplified form, in the form of 2 products, can be easily solved
in a trig equation.
Sep 11, 2016
Explanation:
#= frac{1}{cosx} - frac{1}{sinx}#
#= secx - cscx#