How do you solve #-4/7x=6#?

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Answer 1 · 2016-09-11T16:49:04

#x = -21/2 = -10 1/2 = -10.5#

#-4/7x = 6#

#-4/7# is the only number we need to get rid of to be able to find #x#

Multiply by its reciprocal. (Same as the multiplicative inverse)

#rarr# This will allow the entire number to cancel.
#rarr# Remember to multiply by the same number on BOTH sides.

#color(red)(-7/4) xx -4/7x = color(red)(-7/4)xx 6#

#color(red)(-cancel7/cancel4) xx -cancel4/cancel7x = color(red)(-7/cancel4^2)xx cancel6^3 " " (-xx- =+)#

#x = -21/2 = -10 1/2 = -10.5#