How do you solve #60< 2( 2x - 4) - 6( - x - 3)#?

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Answer 1 · 2016-09-12T14:57:51

#x>5#

Multiply out the brackets using the distributive law. Be careful of a negative sign before a bracket - the signs will change!

Treat the inequality in the same way as an equation.

#60< 2( 2x - 4) - 6( - x - 3)#

#60< 4x - 8 +6x +18#

#60 < 10x +10" "larr# add 10 to both sides

#60-10 < 10x#

#50<10x#

#5< x#

This can also be written as #x>5#