Is the reaction of #"lead sulfide"# with #"dioxygen gas"# to give #"lead oxide"#, and #"sulfur dioxide"#, a redox reaction?

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Is the reaction of #"lead sulfide"# with #"dioxygen gas"# to give #"lead oxide"#, and #"sulfur dioxide"#, a redox reaction?

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Answer 1 · 2016-09-13T05:38:35

This is clearly a redox reaction:

Dioxygen gas is reduced to oxide anion; sulfide anion is oxidized to sulfur dioxide.

Explanation:

#"Lead sulfide + oxygen gas "rarr" Lead Oxide + sulfur dioxide"#

#PbS(s) + 3/2O_2(g) rarr PbO(s) + SO_2(g)#

Sulfide anion is oxidized to sulfur dioxide; dioxygen gas is reduced to oxide anion. This is formally a 6 electron transfer. Is this balanced? How could I remove the non-integral coefficient?

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Is the reaction of #"lead sulfide"# with #"dioxygen gas"# to give #"lead oxide"#, and #"sulfur dioxide"#, a redox reaction?

1 Answer

Explanation:

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