How do you solve #2d - 9= - 16d + 3( 6d - 3)#?

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Answer 1 · 2016-09-13T18:27:01

#x# has any value

#2d - 9= - 16d + 3( 6d - 3)" "larr# get rid of brackets

#2d - 9= - 16d + 18d - 9#

#-9+9 =2d -2d#

#0=0#

This is obviously a true statement, but there is no #x# that we can solve for.

This is a special type of equation called an identity which will be true for any value of x.

#x# has any value