Question

The sum of three consecutive numbers is 117. What is the smallest of the three numbers?

Answer 1

`38`

Explanation:

Let `a, a+1,a+2` be the three consecutive numbers,

`=> a+a+1+a+2=117`
`=> 3a+3 =117`
`=> 3a=114`
`=> a=38`
`=> a+1=39, a+2=40`
the smallest of the three numbers is `a=38`