How do you simplify $\sqrt{28 x} + \sqrt{63 x}$ $sqrt(28x)+sqrt(63x)$ ?

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Answer 1 · 2016-09-14T16:21:47

$= 5 \sqrt{7 x}$ $=5sqrt(7x)$

$\sqrt{28 x} + \sqrt{63 x}$ $sqrt(28x)+sqrt(63x)$

$= \sqrt{4 \times 7 x} + \sqrt{9 \times 7 x}$ $=sqrt(4times7x)+sqrt(9times7x)$

$= 2 \sqrt{7 x} + 3 \sqrt{7 x}$ $=2sqrt(7x)+3sqrt(7x)$

$= 5 \sqrt{7 x}$ $=5sqrt(7x)$

How do you simplify √28x+√63xsqrt(28x)+sqrt(63x)?