How do you solve #x+ 8- \frac{20}{x} = 0#?

1 Answer
Sep 14, 2016

#x=+2" and "x=-10#

Explanation:

Given:#" "x+8-20/x=0#

We need to remove #x# as a denominator.

#color(brown)("This is one approach. dc shows another approach.")#
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Add #20/x# to both sides isolating the term #20/x#

#x+8=20/x#

Multiply both sides by #x#

#x(x+8)=20xx x/x#

#x^2+8x=20#

Subtract 20 from both sides

#x^2+8x-20=0 larr" now we have our quadratic equation"#

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Note that #2xx10=20" and "10-2=8# so we must have the form:

#(x-2)(x+10)=0" "# as #(-2)xx10 = -20# as required

Thus the 2 solutions are: #x=+2" and "x=-10#