How do you solve #1-(2x)/7=(x+6)/3#?

1 Answer
Sep 16, 2016

#x = -21/13#

Explanation:

As it is an equation with fractions, we can get rid of the denominators by multiplying by the LCD which is #21#

#color(white)(xxxxxxxxx)1-(2x)/7=(x+6)/3#

#color(blue)(21xx)1-color(blue)(cancel21^3/1xx)(2x)/cancel7=color(blue)(cancel21^7/1xx)((x+6))/cancel3#

#color(white)(xxxxxxxxx)21-6x = 7x+42#

#color(white)(xxxxxxxxx)21-42 = 7x +6x#

#color(white)(xxxxxxxxxx)-21 = 13x#

#color(white)(xxxx.xxxxx)-21/13 = x#