How do you write the first six terms of the sequence #a_n=(-n)^3#?

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Answer 1 · 2016-09-16T11:37:25

#a_(1) = - 1#

#a_(2) = - 8#

#a_(3) = - 27#

#a_(4) = - 64#

#a_(5) = - 125#

#a_(6) = - 216#

We have: #a_(n) = (- n)^(3)#

In order to write the first six terms of the sequence we simply substitute #n# with the number of the term:

#=> a_(1) = (- 1)^(3) = - 1#

#=> a_(2) = (- 2)^(3) = - 8#

#=> a_(3) = (- 3)^(3) = - 27#

#=> a_(4) = (- 4)^(3) = - 64#

#=> a_(5) = (- 5)^(3) = - 125#

#=> a_(6) = (- 6)^(3) = - 216#