How do you solve #6( - 3x - 2) < - 12- 4x#?

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Answer 1 · 2016-09-17T03:58:28

The solution is #x>0#.

#6(-3x-2)<-12-4x#

Distribute:
#-18x-12<-12-4x#

Add 4x to both sides:
#-18x-12<-12-4x#
#+4xcolor(white)(AAAAAAAAAAAAAAA)+4x#
#-14x-12<-12#

Add 12 to both sides:
#-14x-12<-12#
#color(white)(AAAAAA)+12color(white)(AAAA)+12#
#-14xcolor(white)(AAAAA)<# #color(white)(AAA)0#

Divide both sides by -14.
When dividing by a negative, switch the direction of the inequality.

#(-14x)/-14<0/-14#

#x>0#