What is the derivative of #f(x) = 2 tan^(2)x-sec^(2)x#? Calculus Differentiating Trigonometric Functions Derivatives of y=sec(x), y=cot(x), y= csc(x) 1 Answer Sasha P. Sep 18, 2016 #2secx(2secx-tanx)# Explanation: #(df)/dx=d/dx(2tan^2x-sec^2x)=2d/dx(tan^2x)-d/dx(sec^2x)=# #4d/dx(tanx)-2d/dx(secx)=4sec^2x-2secxtanx=# #=2secx(2secx-tanx)# Answer link Related questions What is Derivatives of #y=sec(x)# ? What is the Derivative of #y=sec(x^2)#? What is the Derivative of #y=x sec(kx)#? What is the Derivative of #y=sec ^ 2(x)#? What is the derivative of #y=4 sec ^2(x)#? What is the derivative of #y=ln(sec(x)+tan(x))#? What is the derivative of #y=sec^2(x)#? What is the derivative of #y=sec^2(x) + tan^2(x)#? What is the derivative of #y=sec^3(x)#? What is the derivative of #y=sec(x) tan(x)#? See all questions in Derivatives of y=sec(x), y=cot(x), y= csc(x) Impact of this question 4635 views around the world You can reuse this answer Creative Commons License