How do you solve #106= 228- u#?

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Answer 1 · 2016-09-18T03:35:08

#u=122#

First, what you want to do is get the numbers and variable (the letter u) on opposite sides of the equation.

Subtract 228 on both sides of the equation to get #u# by itself like this:

#106 =228 - u#
#-228 -228#

On the left side of the equation you get #-122# because #106-228 = -122#, and on the right side you are just left with #-u# because #228-228 =0#.

Now you're left with:

#-122 = -u#

Next, we have to divide both sides by #-1# to make #u# positive. The minus signs drop out since the numerator and denominator are both negative.

#(-122)/(-1) = (-u)/(-1)#

Therefore, #u=122#

Answer 2 · 2016-09-18T11:28:50

u=228-106
u=122