Question

How do you solve `2^(x-1)=23`?

Answer 1

`:. x~~5.5236`.

Explanation:

`2^(x-1)=23 rArr 2^x.2^-1=23 rArr 2^x=2*23=46`

Taking, `log_10` of both sides,

`log_10 2^x=log_10 46`

`:. x*log_10 2=log_10 46`.

`:. x=log_10 46/log_10 2=1.6628/0.3010~~5.5236`.