How many moles of sodium bicarbonate, #NaHCO_3#, are in 508g, of #NaHCO_3#?

1 Answer
anor277
Sep 19, 2016

Almost #6*mol#.

Explanation:

The molar mass of #NaHCO_3# #=# #84.01*g*mol^-1#.

Thus, #"moles of sodium bicarbonate"# #=# #"Mass"/"Molar Mass"#

#=# #(508*cancelg)/(84.01*cancelg*mol^-1)# #=# #??mol#

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