Question

How do you simplify `(5cosphi)/sin^2phi*(sin^2phi-sinphicosphi)/(sin^2phi-cos^2phi)`?

Answer 1

`(5 cotphi)/(sinphi+cosphi)`

Explanation:

`(5cosphi)/sin^2phi*(sin^2phi-sinphicosphi)/(sin^2phi-cos^2phi)=`

#(5cosphi)/sin^2phi*(sin phi(sinphi-cosphi))/((sinphi-cosphi) (sinphi+cosphi)) =#

`(5cosphi)/(sinphi(sinphi+cosphi))=`

`(5 cotphi)/(sinphi+cosphi)`