Question

How do you solve `4( x + 2) + x + 1= 2x - 3+ 3( x + 4)`?

Answer 1

`x in RR, " "x` has any value

Explanation:

`4( x + 2) + x + 1= 2x - 3+ 3( x + 4) " "larr` remove brackets

`4x + 8 + x + 1= 2x - 3+ 3x + 12" "larr` simplify

`color(white)(xxxxxx)5x +9 = 5x +9`

`color(white)(xxxxxxxxxx)0 = 0`

This is a true statement, but there is no `x` left to solve for.

This is a special kind of equation called an identity which is true for any value of `x`.

`x` has any value.