How do you solve #|\frac{6x + 1}{x - 1} | = 3#?

1 Answer
Sep 21, 2016

#x=-4/3# or #x=2/9#

Explanation:

If #abs((6x+1)/(x-1))=3#
then either #{:((6x+1)/(x-1)=+3,color(white)("XXX")orcolor(white)("XXX"),(6x+1)/(x-1)=-3), (rarr 6x+1=3x-3,,rarr6x+1=-3x+3), (rarr 3x=-4,,rarr9x=2), (rarrx=-4/3,,rarrx=2/9) :}#