A ball with a mass of #6 kg# moving at #4 m/s# hits a still ball with a mass of #7 kg#. If the first ball stops moving, how fast is the second ball moving?

1 Answer
Sep 22, 2016

#v_2^'=3.43" "m/s" rounded the two decimal place"#

Explanation:

#"Momentum before collision"#
#".........................................."#
#m_1=6 " "kg" " "'mass of the first object'"#
#v_1=4 " "m/s" ""'velocity of the first object'"#
#vec P_1=m_1*v_1=6*4=24" " kg*m/s" Momentum of the first object"#

#m_2=7" "kg" 'mass of the second object'"#
#v_2=0" velocity of the second object"#
#vec P_2=m_2*v_2=7*0=0" Momentum of the second object"#

#Sigma vec P_b=vec P_1+vec P_2" vectorial sum of the momentums before collision"#

#Sigma vec P_b=24+0=24 " "kg*m/s#

#"Momentum after collision"#
#"........................................."#
#m_1=6" "kg#
#v_1^'=0" the first ball is stopping"#
#vec P_1^'=m_1*v_1^'=6*0=0" Momentum of the first object"#

#m_2=7 " "kg#
#v_2^'=?" velocity of the second ball"#
#vec P_2^'=m_2*v_2^'=7v_2^'#

#"The conservation of momentum"#
#"..................................................."#

#Sigma vec P_b=Sigma vec P_a#

#24=0+7v_2^'#

#v_2^'=24/7#

#v_2^'=3.43" "m/s" rounded the two decimal place"#