How do you solve #3( x + 2)^{2} = 100#?

2 Answers
Sep 22, 2016

#x = -2+-(10sqrt(3))/3#

Explanation:

Multiply both sides by #3# to get:

#3^2(x+2)^2 = 100*3#

Take the square root of both sides, considering both positive and negative square roots to find:

#3(x+2) = +-10sqrt(3)#

Divide both sides by #3# to get:

#x+2 = +-(10sqrt(3))/3#

Subtract #2# from both sides to get:

#x = -2+-(10sqrt(3))/3#

Sep 22, 2016

#x=-2+-(10sqrt3)/3#

Explanation:

Given:#" "3(x+2)^2=100#

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("With practice you will be able to do some of the")# #color(blue)("manipulation in your head, use shortcuts and generally be faster.")#

Divide both sides by 3

#(x+2)^2=100/3#

Square root both sides

#sqrt((x+2)^2) =sqrt100/sqrt3#

#x+2=+-10/sqrt3#

Mathematicians do not like to have a root in the denominator if they can help it. So lets get rid of it!

Write as: #" color(brown)(x+2=+-10/sqrt3color(blue)(xx1)#

but you may write 1 as: #" "1=sqrt3/sqrt3" "# giving:

#" color(brown)(x+2=+-10/sqrt3color(blue)(xxsqrt3/sqrt3)#

#x+2=+-(10sqrt(3))/3#

Subtract 2 from both sides

#x=+-(10sqrt3)/3-2#

#x=-2+-(10sqrt3)/3#