How do you solve #\frac{2x + 4}{2} - \frac{3x}{x - 4} = x#?

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Answer 1 · 2016-09-23T13:25:51

#x=-8#

#(2x+4)/2-(3x)/(x-4)=x#

#((2x+4)(x-4)-6x)/(2(x-4))=x#

#(2x+4)(x-4)-6x=2x(x-4)#

#2x^2+4x-8x-16-6x=2x^2-8x#

#cancel(2x^2)+4x-cancel(8x)-16-6x=cancel(2x^2)-cancel(8x)#

#-2x=16#

#x=-8#