How do you find the limit of #(1+2x) ^(1/2 ln x)# as x approaches infinity?

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Answer 1 · 2016-09-23T22:42:14

#oo#

#lim_(x to oo) (1+2x) ^(1/2 ln x)#

well,

#lim_(x to oo) ln x = oo#

and

#lim_(x to oo) (1+2x) = oo#

So this is only going one way :-)

#oo^oo#