How do you determine if $4 x^{2} - 4$ $4x^2 - 4$ is an even or odd function?

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Answer 1 · 2016-09-24T06:33:36

A function $f (x)$ $f(x)$ is said to be odd if $f (- x) = - f (x)$ $f(-x)=-f(x)$

AND

A function $f (x)$ $f(x)$ is said to be even if $f (- x) = f (x)$ $f(-x)=f(x)$

In our case the given function is $f (x) = 4 x^{2} - 4)$ $f(x)=4x^2-4)$

If we plug in $x = - x$ $x=-x$ we get

$f (- x) = 4 {(- x)}^{2} - 4 = 4 x^{2} - 4 = f (x) \to$ $f(-x)=4(-x)^2-4=4x^2-4=f(x)->$ This means $f (x)$ $f(x)$ is EVEN

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