How do you solve #\frac{- 8}{7} k + \frac{- 4}{7} = - 3- \frac{7}{9} k#?

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Answer 1 · 2016-09-24T09:02:16

#k = 153/23#

In an equation which has fractions you can get rid of the fractions by multiplying EACH term by the LCD (in this case it is 63).

#\frac{- 8}{7} k + \frac{- 4}{7} = - 3- \frac{7}{9} k" "larr xx63# and cancel

#\frac{- 8xxcancel63^9}{cancel7} k + \frac{- 4xxcancel63^9}{cancel7} = - 3xx63- \frac{7xxcancel63^7}{cancel9} k#

#-72k-36 = -189 -49k#

#189-36 = 72k -49k#

#153 = 23k#

#k = 153/23#