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Answer 1 · 2016-09-25T12:08:03

#M(x/2 ; (y-3)/2)#

The midpoint is found from finding:

"The average of the x-values and the average of the y-values"

As a formula : #M((x_1+x_2)/2 ; (y_1+y_2)/2)#

From the given points #V(-2,-6) and W(x+2, y+3)#

#M((-2+x+2)/2 ; (-6+y+3)/2)#

#M(x/2 ; (y-3)/2)#

Answer 2 · 2016-09-25T12:12:19

Midpoint Formula for two points #(x_1,y_1) and (x_2,y_2) # is as follows
#((x_1 + x_2)/2 , (y_1 + y_2)/2)#

Something like you're averaging the two points' #x#- and #y#-values.

Inserting given values we get the coordinates of the midpoint as
#((-2 + (x+2))/2 , (-6 + (y+3))/2)#
#=>(x/2 , ( y-3)/2)#