How do you find four consecutive integers whose sum is 366?

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Answer 1 · 2016-09-26T11:06:20

#90, 91, 92, 93#

Let n be the first integer on the series:

#:. n+(n+1)+(n+2)+(n+3)= 366#

#4n+6=366#

#4n=360#

#n=90#

Thus the four consequtive integers are:

#90, 91, 92, 93#