How do you solve #-\frac{9}{x - 3} = - \frac{3}{x - 5}#?

2 Answers
Sep 26, 2016

Distribute the negative and cross multiply

Explanation:

Distribute the negative to the numerator and cross multiply
#-9(x-5) = -9 x +45#

#-3(x-3)= -3x+9#

Combine like terms by subtracting 45 on both sides of the equation
#-9x +45 = -3x +9#

#-9x=-3x -36#

Combine like terms by adding 3x on both sides of the equations
#-6x=-36#

Isolate x by dividing by -6
#x=6#

Sep 26, 2016

#x = 6#

Explanation:

Decide what to do with the negative at the front of each fraction.
It may only be used with the numerator OR the denominator - not both.

#9/(color(red)(-)(x-3)) = (color(red)(-3))/(x-5)" "larr# now cross multiply

#9(x-5) = color(red)(+3)(x-3) " "larr# remove the brackets

#9x-45 = 3x-9 " "larr# re-arrange the terms

#9x-3x = 45-9" "larr# simplify each side

#6x = 36" "larrdiv 6#

#x = 6#

Of course, the simplest solution with the negative signs, is to multiply each fraction by #-1#, or move each to the other side to make each term positive.

#3/(x-5) = 9/(x-3)" "larr# cross multiply and proceed as above.