How do you multiply #(2m - 1) ( m + 2)#?

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Answer 1 · 2016-09-27T06:47:56

#2m^2+3m-2#

start off by writing
#(2m-1)(m+2)#

multiply by distributing with #2m# first
#(2m)(m)#
#(2m)(2)#

you now have
#2m^2+4m#

distribute with the #-1# now
#(-1)(m)#
#(-1)(2)#

you get
#-1m-2# OR #-m-2#

put the products together and you get
#2m^2+4m-1m-2#

combine like terms and you have your answer
#2m^2+3m-2#